( Skip thermal inertia test.
  The left node of a bar is kept at temperature 0.
  The right node is heated with a heat source 1.
  Since thermal inertia is skipped, we should find
  k * dT/dx = heat source.
  Here the conductivity k is 1.
  The length of the bar is 1, so that the temperature
  of the right node should become 1.
  Iterations are needed, because TOCHNOG essentially is an explicit
  program. )

echo -no
number_of_space_dimensions 1
condif_temperature
end_initia

options_inertia -no

node 1  0 
node 2  1 
element 1  -bar2 1 2 

bounda_unknown 1  1 -temp
bounda_time    1  0.0 0.0 100. 0.
bounda_force   2  2 -temp
bounda_time    2  0.0 1.0 100.0 1.

group_type 0  -condif
group_condif_density 0  1.0
group_condif_capacity 0  1.0
group_condif_conductivity 0  1.0

control_timestep                        0  0.1 0.1
(control_print                           0  -time_current -node_dof)

target_item 0   -node_dof 2 -temp
target_value   0   1.0 1.e-4
end_data
